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Differentiator
11.5.1. Basic Circuit
If the resistor and capacitor of the integrator in Fig. 11.7 are interchanged, we obtain the differentiator shown in Fig. 11.14. The application of KCL to the summing point yields the relationship
11.7.1. Logarithm
A logarithmic amplifier must produce an output voltage that is proportional to the logarithm of the input voltage. It is therefore possible to make use of the diode characteristic
In this equation, Is is the saturation leakage current, is the thermal voltage, and n is a correction factor between 1 and 2. For the forward-biased diode, when IA>> IS, (11.8) can be approximated with good accuracy by
Hence, the forward voltage is
which is the required logarithmic function. The simplest way of using this relationship for computation of the logarithm is shown in Fig. 11.20, where a diode is incorporated into the feedback loop of an operational amplifier. This amplifier converts the input voltage Vi to a proportional current IA = Vi / R1. At the same time, the voltage Vo = —VAC appears at its low-impedance output. Therefore
or at room temperature.
The usable range is limited by two effects. The diode possesses a parasitic series resistance, across which a considerable voltage is present at high currents, leading to errors in the computation of the logarithm. In addition, the correction factor n is current-dependent. A satisfactory accuracy can therefore only be achieved over an input voltage range of one or two decades. The unfavorable effect of the varying correction factor n can be eliminated by replacing the diode D by a transistor T, as shown in Fig. 11.21. If IC >> ICS, for the collector current we can write
and hence
The output voltage of the transistor logarithmic amplifier shown in Fig. 11.21 is therefore:
11.7.2. Exponential Function
Figure 11.24 shows an exponential function amplifier whose design is analogous to that of the logarithmic amplifier in Fig. 11.21. When a negative voltage is applied to the input, the current flowing through the transistor may be written as
and the output voltage is therefore
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